## Chemistry (12th Edition)

Published by Prentice Hall

# Chapter 10 - Chemical Quantities - 10 Assessment: 62

#### Answer

100.0869 g/mol = Molar Mass

#### Work Step by Step

40.078 g/mol +12.0107 g/mol +3(15.9994 g/mol)=100.0869 g/mol Use a periodic table in order to compute the molar mass of CaCo3

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