Chemistry 10th Edition

Published by Brooks/Cole Publishing Co.
ISBN 10: 1133610668
ISBN 13: 978-1-13361-066-3

Chapter 4 - The Structure of Atoms - Exercises - Atomic Composition, Isotopes, and Atomic Weights - Page 166: 37

Answer

The atomic weight of silicon is equal to $28.0855amu$.

Work Step by Step

Considering the natural abundance of silicon isotopes, we can obtain its atomic weight by following: $Ar(Si)=0.9223\times27.9769amu+0.0467\times28.9765amu+0.0310\times29.9738amu=28.0855amu$ We need to multiple the natural abundance of each of the silicon isotopes by its mass and then calculate the sum of those products in order to obtain the atomic weight of silicon.
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