Answer
3.44 L
Work Step by Step
2 mol $HBr$ is required to react completely with 1 mol of $Ca(OH) _{2}$.
$\implies \text{Moles of HBr}=2\times 0.960=1.92\,mol$
$\text{Volume of the HBr solution}=\frac{\text{Moles of HBr}}{\text{Molarity}}$
$=\frac{1.92\,mol}{0.558\,M}=3.44\,L$
