Chapter 3 - Chemical Equations and Reaction of Stoichiometry - Exercises - Percent Yield from Chemical Reactions - Page 109: 43

146.22 g S

Theoretical yield = Actual yield / (Percent Yield/100) = 80.0 g CS2 / 0.92 = 87.0 g CS2 Divide by the atomic mass: 87.0g/ 76.14g/mol = 1.14 mol CS2 Multiply by the mole ratio: 1.14 mol CS2 x (4 mol S/1 mol CS2) = 4.56 mol S Multiply by the atomic mass: 4.56 mol S x 32.065g/mol = 146.22 g S