Chemistry 10th Edition

Published by Brooks/Cole Publishing Co.
ISBN 10: 1133610668
ISBN 13: 978-1-13361-066-3

Chapter 3 - Chemical Equations and Reaction of Stoichiometry - Exercises - Concentrations of Solutions - Molarity - Page 110: 64

Answer

5.08$\times$$10^{3}$ mL

Work Step by Step

Number of moles= Mass in grams/ Molar mass= $\frac{25 g}{40 gmol^{-1}}$= 0.625 mol Volume of solution in L = Number of moles of solute/Molarity =0.625 mol/0.123 M =5.08 L=5.08$\times10^{3}$ mL
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