#### Answer

There are 882. g of $NaHCO_3$

#### Work Step by Step

1. Find the number of moles of $NaHCO_3$:
Each $NaHCO_3$ has 1 carbon. So:
$10.5mol(C) \times \frac{1mol(NaHCO_3)}{1mol(C)} = 10.5 mol(NaHCO_3)$
2. Determine the molar mass of this compound $(NaHCO_3)$:
22.99* 1 + 1.008* 1 + 12.01* 1 + 16.00* 3 = 84.01g/mol
3. Calculate the mass ($NaHCO_3$)
$mm(g/mol) = \frac{mass(g)}{n(mol)}$
$mm(g/mol) * n(mol) = mass(g)$
$ 84.01 * 10.5 = mass(g)$
$882. = mass(g)$