Chemistry 10th Edition

Published by Brooks/Cole Publishing Co.
ISBN 10: 1133610668
ISBN 13: 978-1-13361-066-3

Chapter 2 - Chemical Formulas and Composition Stoichiometrhy - Exercises - The Law of Multiple Proportions - Page 77: 73

Answer

58.0% M in MO

Work Step by Step

If the M2O substance is 73.4% M by mass, then it is 26.6% oxygen by mass. This means that if you had one mole of M2O: 26.6= 15.9994g O\div xg M2O\times 100 Or that 60.148 would be the grams of M2O in a mole. 60.148 - 15.9994= 44.15 as the mass of the 2M atoms; each M is 22.07 g/mol So for MO: ?% M in MO = 22.07g M\div 22.07 + 15.9994g MO\times 100 = 58.0% M in MO
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