Chemistry 10th Edition

Published by Brooks/Cole Publishing Co.
ISBN 10: 1133610668
ISBN 13: 978-1-13361-066-3

Chapter 2 - Chemical Formulas and Composition Stoichiometrhy - Exercises - Composition Stoichiometry - Page 75: 47


46.87% Fe

Work Step by Step

Mass % of an element= (Mass of that element in the compound÷Molar mass of the compound)×100 Here, Molar mass of Iron(II)Phosphate = (3× Atomic mass of Fe)+ (2×Atomic mass of P)+ (8× Atomic mass of O) = 357.48 g/mol Mass of Fe= 3× Atomic mass of Fe= 167.535 g/mol. Then, Mass percent of Fe = $\frac{167.535}{357.48}$×100= 46.87%
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