Answer
$pH = 7.75$
Work Step by Step
1. Using the Henderson–Hasselbalch equation:
$pH = pKa + log(\frac{[Base]}{[Acid]})$
$pH = 7.45 + log(\frac{0.0444}{0.0222})$
$pH = 7.45 + log(2)$
$pH = 7.45 + 0.301$
$pH = 7.75$
Chemistry 10th Edition
by Whitten, Kenneth W.; Davis, Raymond E.; Peck, Larry; Stanley, George G.
Published by
Brooks/Cole Publishing Co.
ISBN 10:
1133610668
ISBN 13:
978-1-13361-066-3
Chapter 19 - Ionic Equilibria II: Buffers and Titration Curves - Exercises - The Common Ion Effect and Buffer Solutions - Page 773: 11
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