## Chemistry 10th Edition

$pH = 7.75$
1. Using the Henderson–Hasselbalch equation: $pH = pKa + log(\frac{[Base]}{[Acid]})$ $pH = 7.45 + log(\frac{0.0444}{0.0222})$ $pH = 7.45 + log(2)$ $pH = 7.45 + 0.301$ $pH = 7.75$