#### Answer

$[HNO_3] = 3.02 \times 10^{-4}$

#### Work Step by Step

1. Find $[H_3O^+]$
$[H_3O^+] = 10^{-pH}$
$[H_3O^+] = 10^{- 3.52}$
$[H_3O^+] = 3.02 \times 10^{- 4}M$
2. Since this is a strong acid: $[HNO_3] = [H_3O^+] = 3.02 \times 10^{-4}$

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ISBN 10:
1133610668

ISBN 13:
978-1-13361-066-3

$[HNO_3] = 3.02 \times 10^{-4}$

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