Chemistry 10th Edition

Published by Brooks/Cole Publishing Co.
ISBN 10: 1133610668
ISBN 13: 978-1-13361-066-3

Chapter 14 - Solutions - Exercises - Concentrations and Solutions - Page 544: 31

Answer

$X_{ethanol}=0.274$ $X_{water}=0.726$

Work Step by Step

Mass of ethanol= $55.0\,mL\times0.789\,g/mL=43.395\,g$ Mass of water= $45.0\,mL\times1.00\,g/mL=45.0\,g$ Number of moles of $C_{2}H_{5}OH=\frac{43.395\,g}{46.07\,g/mol}$ $=0.9419\, mol$ Number of moles of water= $\frac{45.0\,g}{18.0\,g/mol}$ $=2.50\, mol$ Mole fraction of water, $X_{water}=\frac{\text{moles of water}}{\text{moles of water}+\text{moles of ethanol}}$ $=\frac{2.50\,mol}{2.50\,mol+0.9419\,mol}$ $=0.726$ Mole fraction of ethanol, $X_{ethanol}=\frac{\text{moles of ethanol}}{\text{moles of water}+\text{moles of ethanol}}$ $=\frac{0.9419\,mol}{2.50\,mol+0.9419\,mol}=0.274$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.