Answer
a) No. Here the temperature in Celcius scale is doubled. But, we can expect volume to double only if the temperature is doubled in Kelvin scale.(Charles's law is based on Kelvin scale.)
b) 33.0 L
c) 42.5 L
d) 29.0 L
Work Step by Step
b) $\frac{V_{1}}{T_{1}}$ = $\frac{V_{2}}{T_{2}}$ ( Charles's law)
Then, $V_{2}$ =$\frac{31.0L\times311K}{292K}$ =33.0 L
c) $V_{2}$ = $\frac{31.0L\times 400K}{292K}$ = 42.5 L
d) $V_{2}$ = $\frac{31.0L\times273K}{292K}$ = 29.0 L
