Answer
$2.20\times10^{3}\,psi$
Work Step by Step
$150.\,atm= 150\,atm\times\frac{1.01325\times10^{5}\,Pa}{1\,atm}$
$=151.9875\times10^{5}\,Pa\times\frac{1\,psi}{6895\,Pa}$
$=2.20\times10^{3}\,psi$
Chemistry 10th Edition
by Whitten, Kenneth W.; Davis, Raymond E.; Peck, Larry; Stanley, George G.
Published by
Brooks/Cole Publishing Co.
ISBN 10:
1133610668
ISBN 13:
978-1-13361-066-3
Chapter 12 - Gases and the Kinetic-Molecular Theory - Exercises - Basic Ideas - Page 438: 10
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