Answer
$c(NaOH)=0.4361M$
Work Step by Step
By considering stoichiometric coefficients, we can observe that the amount of benzoic acid required is equal to the amount of sodium hydroxide. Hence,
$n(NaOH)=n(C_{6}H_{5}COOH)= \frac{m(C_{6}H_{5}COOH)}{M(C_{6}H_{5}COOH)}=\frac{1.862g}{122\frac{g}{mol}}=0.01526mol$
We can obtain the molarity of $NaOH$ solution knowing its volume:
$c(NaOH)=\frac{n(NaOH)}{V(NaOH)}=\frac{0.01526mol}{0.035dm^3}=0.4361M$
