Answer
$V(NaOH)=30.94ml$
Work Step by Step
The following is the neutralization reaction of sodium hydroxide by sulfuric acid:
$2NaOH + H_{2}SO_{4} \rightarrow Na_{2}SO_{4} + 2H_{2}O$
By considering stoichiometric coefficients, we can observe that the amount of sodium hydroxide required is twice the amount of sulfuric acid. Hence,
$n(NaOH)=2\times n(H_{2}SO_{4})=2\times c(H_{2}SO_{4})\times V(H_{2}SO_{4})=2\times 0.1023\frac{mol}{dm^3}\times 0.02941dm^3=0.006017286mol$
We can obtain the volume of $NaOH$ solution knowing its concentration:
$V(NaOH)=\frac{n(NaOH)}{c(NaOH)}=\frac{0.006017286mol}{0.1945\frac{mol}{dm^3}}=0.03094dm^3=30.94ml$
