Chemistry 10th Edition

Published by Brooks/Cole Publishing Co.
ISBN 10: 1133610668
ISBN 13: 978-1-13361-066-3

15 - Chemical Thermodynamics - Exercises - Internal Energy and Changes in Internal Energy - Page 604: 76

Answer

-336 J

Work Step by Step

Internal energy $\Delta U=q+w$ where $q$ the heat transferred and $w$ is the work done. Work received by the system is positive and work performed by the system is negative. Therefore, total work $w=96\,J-257\,J=-161\,J$ Heat absorbed is positive and heat released is negative. As heat is released, Heat transfer $q=-175\,J$ So, $\Delta U=(-161\,J)+(-175\,J)=-336\,J$
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