Chemistry 10th Edition

Published by Brooks/Cole Publishing Co.
ISBN 10: 1133610668
ISBN 13: 978-1-13361-066-3

15 - Chemical Thermodynamics - Exercises - Internal Energy and Changes in Internal Energy - Page 604: 75

Answer

-67200 J

Work Step by Step

Internal energy $\Delta U=q+w$ where $q$ the heat transferred and $w$ is the work done. Work received by the system is positive and work performed by the system is negative. Here, work is performed by the system. Therefore, $w=-720.\,L\cdot atm=-720.\,L\cdot atm\times\frac{101.325\,J}{1\,L\cdot atm}=-72954\,J$ Heat absorbed is positive and heat released is negative. As heat is absorbed, Heat transfer $q=+5750.\,J$ So, $\Delta U=(5750\,J)+(-72954\,J)=-67200\,J$
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