Molecular Biology of the Cell 6th Edition

Published by Garland Science
ISBN 10: 0815344325
ISBN 13: 978-0-81534-432-2

Chapter 2 - End-of-Chapter - Problems: 2-15

Answer

69.2 W

Work Step by Step

Rate of ATP usage = $5 \times 10^{13} \times 10^{9}$ = $5 \times 10^{22}$ molecules/min $(5 \times 10^{22}) \div 60$ = $8.33 \times 10^{20}$ molecules/second $(8.33 \times 10^{20}) \div (6.02 \times 10^{23}) = 1.38 \times 10^{-3}$ mol/second Energy released = $1.38 \times 10^{-3} \times 50$ = $6.92 \times 10^{-2}$ kJ/sec = 69.2 J/sec = 69.2 W
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