Molecular Biology of the Cell 6th Edition

Published by Garland Science
ISBN 10: 0815344325
ISBN 13: 978-0-81534-432-2

Chapter 1 - End-of-Chapter - Problems: 1-7

Answer

See the explanation below.

Work Step by Step

The given conditions in the scenario show a linkage to a common ancestor. Therefore, there are 3 possible solutions. First, the Archea-eukaryotes may have split from eubacteria, resulting in the seperation of archea from eukaryotes. Second, the Eubacteria -archea may have split from eukaryotes, and then eubacteria separted from archea. The last scenario is that eubacteria - eukaryotes split from archea, which was then followed by the separation of eubacteria from eukaryotes.
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