Answer
It would take two CDs for the entire human genome.
Work Step by Step
The entire human genome is $3 * 10^{9}$ nucleotide pairs long and a CD stores $4.8 * 10^{9}$. So $3 * 10^{9}$ * 2 bits / $4.8 * 10^{9}$ = 2
Essential Cell Biology, 4th Edition
by Alberts, Bruce; Bray, Dennis; Hopkin, Karen; Johnson, Alexander D,; Lewis, Julian; Raff, Martin; Roberts, Keith; Walter, Peter
Published by
Garland Science
ISBN 10:
0815344546
ISBN 13:
978-0-81534-454-4
Chapter 5 - DNA and Chromosomes - Questions - Page 194: Question 5-10 B
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