Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapters 1-3 - Cumulative Test - Page 176: 13

Answer

$9^o43'$

Work Step by Step

RECALL: $1^o=60'$ Thus. $25^o15' - 15^o32' \\= 24^o(1^o+15') - 15^o32' \\=24^o(60+15)' - 15^o32' \\=24^o75' - 15^o32'$ Subtract the corresponding parts to obtain: $=(24-15)^o (75-32)' \\=9^o43'$
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