Answer
$\sin120^\circ=\frac{\sqrt3}{2}$
Work Step by Step
We know that $\sin A\cos B+\sin B\cos A=\sin(A+B)$, hence this sum can be simplified to: $\sin(30+90)=\sin120^\circ=\frac{\sqrt3}{2}$
Trigonometry 7th Edition
by McKeague, Charles P.; Turner, Mark D.
Published by
Cengage Learning
ISBN 10:
1111826854
ISBN 13:
978-1-11182-685-7
Chapter 8 - Section 8.2 - Trigonometric Form for Complex Numbers - 8.2 Problem Set - Page 433: 77
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