Answer
$sin\theta = \frac{12}{13}$, $cos\theta =-\frac{5}{13}$
Work Step by Step
For point (-5, 12), it is in the 2nd quadrant, the absolute value (modulus) is $\sqrt{(-5)^2 + 12^2} = 13$, hence,
$sin\theta = \frac{12}{13}$ and $cos\theta =-\frac{5}{13}$
