Answer
$B = 77^\circ$
$B' =103^\circ$
Work Step by Step
$\sin{B} = \dfrac{b \sin{A}}{a} = \dfrac{18 \times \sin{60^\circ}}{16} $
$\sin{B} = 0.974$
$B = 77^\circ$
$B' = 180-B = 103^\circ$
$A+B' =60+103 = 163^\circ <180$
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