Answer
See the steps.
Work Step by Step
$\sin{B} = \dfrac{b \sin{A}}{a} = \dfrac{40 \times \sin{30^\circ}}{10} $
$\sin{B} = 2$
There is no value of $B$ for which $\sin{B}$ is greater than 1.
$\therefore$ There is no solution possible for the triangle.