Answer
$A=55.471^\circ$
$B =45.468^\circ$
$C=79.061^\circ$
Work Step by Step
$\cos{A} = \dfrac{b^2+c^2-a^2}{2bc} = \dfrac{(3.79)^2+(5.22)^2-(4.38)^2}{2 \times 3.79 \times 5.22} = 0.567$
$$\therefore A = \boxed{55.471^\circ}$$
$\cos{B} = \dfrac{a^2+c^2-b^2}{2ac} = \dfrac{(4.38)^2+(5.22)^2-(3.79)^2}{2 \times 4.38 \times 5.22} = 0.701$
$$\therefore B =\boxed{45.468^\circ} $$
$$C = 180-(A+B) = 180-(55.471+45.468) = \boxed{79.061^\circ}$$
