Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 5 - Section 5.4 - Half-Angle Formulas - 5.4 Problem Set - Page 305: 40

Answer

$\dfrac{1}{2+\sqrt{3}} $

Work Step by Step

$\tan{\dfrac{A}{2}} = \dfrac{\sin{A}}{1+\cos{A}} $ $\tan{15} = \dfrac{\sin{30}}{1+\cos{30}} = \dfrac{\dfrac{1}{2}}{1+\dfrac{\sqrt{3}}{2}}$ $\tan{15} = \dfrac{1}{2+\sqrt{3}} $
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