Answer
$\cos{(60)}=\dfrac{1}{2} $
Work Step by Step
$\cos{(A-B)} = \cos{A} \cos{B} + \sin{A} \sin{B}$
$\cos{(15)} \cos{(75)} + \sin{(15)} \sin{(75)} \\= \cos{(15-75)} = \cos{(-60)} = \cos{(60)}=\dfrac{1}{2}$
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