Answer
See the steps.
Work Step by Step
$\tan{(x-\dfrac{\pi}{4})} = \dfrac{\tan{x}-\tan{\dfrac{\pi}{4}}}{1+ \tan{x} \tan{\dfrac{\pi}{4} }}$
$\tan{(x-\dfrac{\pi}{4})} = \dfrac{\tan{x}-1}{\tan{x}+1}$
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