Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 5 - Section 5.2 - Sum and Difference Formulas - 5.2 Problem Set - Page 288: 26

Answer

See the steps.

Work Step by Step

$\tan{(x-\dfrac{\pi}{4})} = \dfrac{\tan{x}-\tan{\dfrac{\pi}{4}}}{1+ \tan{x} \tan{\dfrac{\pi}{4} }}$ $\tan{(x-\dfrac{\pi}{4})} = \dfrac{\tan{x}-1}{\tan{x}+1}$
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