Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 5 - Section 5.1 - Proving Identities - 5.1 Problem Set - Page 280: 84

Answer

$\sin 2x=2\sin x$ is not an identity.

Work Step by Step

$\displaystyle \sin(2\cdot 30^{o})=\sin(60^{o})=\frac{\sqrt{3}}{2}$ $2\displaystyle \sin(30^{o})=2\cdot\frac{1}{2}=1$ $\sin(2\cdot 30^{o})\neq 2\sin(30^{o})$ so $\sin 2x=2\sin x$ is not an identity.
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