Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 4 - Test - Page 268: 30

Answer

$\sin \theta = \sqrt{1 - x^2}$

Work Step by Step

Let $\cos ^ {–1} x = \theta$, then, $\cos \theta = x$ To evaluate, $\sin (\cos ^ {–1} x) = \sin \theta$ We know that, $\sin \theta = \sqrt{1 - \cos ^2 x}$ Using above relations we get $\sin \theta = \sqrt{1 - x^2}$
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