Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 4 - Section 1.5 - More on Identities - 1.5 Problem Set - Page 47: 100

Answer

(d). $\frac{1}{\sin\theta} - \frac{\sin^{2}\theta}{\sin\theta}$ is a valid step

Work Step by Step

To prove any identity, we begin with one side i.e. L.S. and try to transform it to other side i.e. R.S. L.S. of the given expression is- $\frac{1}{\sin\theta} - \sin\theta$ To add both, we will multiply the term $\sin\theta$ by $\frac{\sin\theta}{\sin\theta}$, hence the expression becomes- $\frac{1}{\sin\theta} - \sin\theta.\frac{\sin\theta}{\sin\theta}$ = $\frac{1}{\sin\theta} - \frac{\sin^{2}\theta}{\sin\theta}$ Thus option (d) is a valid step.
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