Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 3 - Section 3.4 - Arc Length and Area of a Sector - 3.4 Problem Set - Page 153: 14

Answer

$\frac{40\pi}{3}\approx41.89$ in

Work Step by Step

We know that the length of the arc $s$ cut off by $\theta$ can be calculated as $s=r\theta$. We are given that $\theta=240^{\circ}$ and $r=10$ in. To convert $\theta$ to radians, we must multiply $\theta$ by $\frac{\pi}{180}$. $\theta=240^{\circ}=240(\frac{\pi}{180})=\frac{240\pi}{180}=\frac{4\pi}{3}$ Therefore, $s=\frac{4\pi}{3}(10)=\frac{4\pi}{3}\times10=\frac{4\pi\times10}{3}=\frac{40\pi}{3}\approx41.89$ in.
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