Answer
$0$
Work Step by Step
The argument above says that $\sin x=\sin(2\pi+x)$ and $\cos x=\cos (2\pi+x)$
Hence here $\cos(2\pi+\frac{\pi}{2})=\cos(\frac{\pi}{2})=0$
Trigonometry 7th Edition
by McKeague, Charles P.; Turner, Mark D.
Published by
Cengage Learning
ISBN 10:
1111826854
ISBN 13:
978-1-11182-685-7
Chapter 3 - Section 3.3 - Definition III: Circular Functions - 3.3 Problem Set - Page 145: 78
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