## Trigonometry 7th Edition

$({\frac{\pi}{6},5}),({{\frac{\pi}{3}},{\frac{5}{2}})},({\frac{2\pi}{3},-5}),({{\pi},{\frac{5}{2}}}),({\frac{7\pi}{6},5})$
given $y=5 \cos(2x-\frac{\pi}{3})$ when $x={\frac{\pi}{6}}$ then $y=5\cos{0}=5$ $x={\frac{\pi}{3}}$ then $y=5\cos{\frac{\pi}{3}}={\frac{5}{2}}$ $x={\frac{2\pi}{3}}$ then $y=5\cos{\pi}=-5$ $x={{\pi}}$ then $y=5\cos{\frac{5\pi}{3}}={\frac{5}{2}}$ $x={\frac{7\pi}{6}}$ then $y=3.\cos{2\pi}=5$ then the final answer is : $({\frac{\pi}{6},5}),({{\frac{\pi}{3}},{\frac{5}{2}})},({\frac{2\pi}{3},-5}),({{\pi},{\frac{5}{2}}}),({\frac{7\pi}{6},5})$