## Trigonometry 7th Edition

(a) Refer to the image below for the drawing. (b) $-\dfrac{5}{6}\pi$ radians (c) Reference angle = $30^o$ or $\dfrac{\pi}{6}$ radians
(a) From the positive x-axis, move 150 degrees clockwise. (refer to the attached image above for the drawing) (b) Convert to radians by multiplying $\dfrac{\pi}{180^o}$ to obtain: $-150^o \cdot \dfrac{\pi}{180^o} = -\dfrac{5}{6}\pi$ radians (c) The angle is in Quadrant III. The reference angle of an angle $\theta$ in Quadrant III is equal to the acute angle that the terminal side makes with the negative x-axis. Thus, the reference angle of the given angle is: $\color{blue}{30^o}=30^o \cdot \dfrac{\pi}{180^o}=\color{blue}{\dfrac{\pi}{6}}$ radians.