Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 3 - Section 3.1 - Reference Angle - 3.1 Problem Set - Page 123: 92

Answer

$\sqrt 3$

Work Step by Step

Given expression is- $4 \sin 60^{\circ} - 2 \cos 30^{\circ}$ = $4.\frac{\sqrt 3}{2} - 2 \frac{\sqrt 3}{2} $ (Substituting exact values) = $2\sqrt 3 - \sqrt 3$ = $\sqrt 3$
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