Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 2 - Section 2.4 - Applications - 2.4 Problem Set - Page 97: 49

Answer

Please refer to the step-by-step part below for the solution.

Work Step by Step

RECALL: $\cot{\theta} = \dfrac{\cos{\theta}}{\sin{\theta}}$ Thus, the left side of the equation is equivalent to: $\require{cancel} \sin{\theta} \cot{\theta}$ $\\=\sin{\theta} \cdot \dfrac{\cos{\theta}}{\sin{\theta}} \\=\cancel{\sin{\theta}} \cdot \dfrac{\cos{\theta}}{\cancel{\sin{\theta}}} \\=\cos{\theta}$ Therefore, $\sin{\theta}\cot{\theta} = \cos{\theta}$
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