Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 2 - Section 2.4 - Applications - 2.4 Problem Set - Page 97: 49


Please refer to the step-by-step part below for the solution.

Work Step by Step

RECALL: $\cot{\theta} = \dfrac{\cos{\theta}}{\sin{\theta}}$ Thus, the left side of the equation is equivalent to: $\require{cancel} \sin{\theta} \cot{\theta}$ $\\=\sin{\theta} \cdot \dfrac{\cos{\theta}}{\sin{\theta}} \\=\cancel{\sin{\theta}} \cdot \dfrac{\cos{\theta}}{\cancel{\sin{\theta}}} \\=\cos{\theta}$ Therefore, $\sin{\theta}\cot{\theta} = \cos{\theta}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.