## Trigonometry 7th Edition

RECALL: $\cot{\theta} = \dfrac{\cos{\theta}}{\sin{\theta}}$ Thus, the left side of the equation is equivalent to: $\require{cancel} \sin{\theta} \cot{\theta}$ $\\=\sin{\theta} \cdot \dfrac{\cos{\theta}}{\sin{\theta}} \\=\cancel{\sin{\theta}} \cdot \dfrac{\cos{\theta}}{\cancel{\sin{\theta}}} \\=\cos{\theta}$ Therefore, $\sin{\theta}\cot{\theta} = \cos{\theta}$