Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 1 - Test: 2

Answer

$x$ = $3\sqrt 3$

Work Step by Step

Using Pythagorean theorem in given Figure 1- $x^{2} + 3^{2} $ = $6^{2}$ Or $x^{2} + 9 $ = $36$ Or $x^{2}$ = $36 - 9$ = 27 Therefore $x$ = $\sqrt {27}$ = $\sqrt {9\times3}$ = $\sqrt {9} \sqrt 3$ $x$ = $3\sqrt 3$
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