## Trigonometry 7th Edition

(a). $\frac{b^{2}+a}{ab}$ (b). $\frac{\cos^{2}\theta+\sin\theta}{\sin\theta\cos\theta}$
(a). Given expression is- $\frac{b}{a} + \frac{1}{b}$ = $\frac{b}{b}\times\frac{b}{a} + \frac{1}{b}\times\frac{a}{a}$ = $\frac{b^{2}}{ab} + \frac{a}{ab}$ = $\frac{b^{2}+a}{ab}$ (b). Given expression is- $\frac{\cos\theta}{\sin\theta} + \frac{1}{\cos\theta}$ = $\frac{\cos\theta}{\cos\theta}\times\frac{\cos\theta}{\sin\theta} + \frac{1}{\cos\theta}\times\frac{\sin\theta}{\sin\theta}$ = $\frac{\cos^{2}\theta}{\sin\theta\cos\theta} + \frac{\sin\theta}{\sin\theta\cos\theta}$ = $\frac{\cos^{2}\theta+\sin\theta}{\sin\theta\cos\theta}$