## Trigonometry 7th Edition

d. - $\sqrt (1-(\frac{1}{4})^{2})$
We know from first Pythagorean identity that- $\sin\theta$ = ± $\sqrt (1-\cos^{2}\theta)$ Given $\theta$ terminates in Q IV. Therefore $\sin\theta$ will be negative- OR $\sin\theta$ = - $\sqrt (1-\cos^{2}\theta)$ $\sin\theta$ = - $\sqrt (1-(\frac{1}{4})^{2})$