Answer
d. - $\sqrt (1-(\frac{1}{4})^{2})$
Work Step by Step
We know from first Pythagorean identity that-
$\sin\theta$ = ± $\sqrt (1-\cos^{2}\theta)$
Given $\theta$ terminates in Q IV. Therefore $\sin\theta$ will be negative-
OR
$\sin\theta$ = - $\sqrt (1-\cos^{2}\theta)$
$\sin\theta$ = - $\sqrt (1-(\frac{1}{4})^{2})$
