Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 1 - Section 1.4 - Introduction to Identities - 1.4 Problem Set - Page 41: 66


d. - $\sqrt (1-(\frac{1}{4})^{2})$

Work Step by Step

We know from first Pythagorean identity that- $\sin\theta$ = ± $\sqrt (1-\cos^{2}\theta)$ Given $\theta$ terminates in Q IV. Therefore $\sin\theta$ will be negative- OR $\sin\theta$ = - $\sqrt (1-\cos^{2}\theta)$ $\sin\theta$ = - $\sqrt (1-(\frac{1}{4})^{2})$
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