Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 1 - Section 1.2 - The Rectangular Coordinate System - 1.2 Problem Set - Page 25: 51



Work Step by Step

The line $x=\frac{1}{2}$ intersects the circle $x^2+y^2=1$ at $(0.5,0.866)$and$(0.5,-0.866)$ as can be seen from the figure. The solution can also be obtained analytically by substituting $x=\frac{1}{2}$ in the equation $x^2+y^2=1$ and solving for $y$ $$y^2 = 1-x^2$$ $$y = \pm \sqrt{1-x^2} = \pm \sqrt{1-(0.5)^2} = \pm \sqrt{\frac{3}{4}}$$ $$\therefore y = \pm \frac{\sqrt{3}}{2} \approx \pm 0.8660$$ $\therefore $ The coordinates are $(0.5,0.866)$and$(0.5,-0.866)$.
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