Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 1 - Section 1.2 - The Rectangular Coordinate System - 1.2 Problem Set - Page 24: 42

Answer

84.85 feet

Work Step by Step

Required throw will be the length of hypotenuse of the right triangle formed by home, first base and second base right angled at first base. Using the given distances and Pythagorean theorem, We get- $Required Distance^{2}$ = $HomeToFirst Base Distance^{2}$ + $FirstToSecond Base Distance^{2}$ $Required Distance^{2}$ = $60^{2}$ + $60^{2}$ = 3600 + 3600 = 7200 Required Distance = $\sqrt (7200)$ = 84.85 feet
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