Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 1 - Section 1.2 - The Rectangular Coordinate System - 1.2 Problem Set - Page 24: 41

Answer

Diagonal Distance from the plane to the runway = 1.3 miles

Work Step by Step

Given approach of the airplane forms a right triangle (as in given figure 22) in which length of diagonal will be the required distance- Given- Horizontal distance = 1.2 miles Altitude of the plane = 2640 feet = $\frac{2640}{5280}$ miles ( Given, 1 mile = 5280 feet) Altitude of the plane = $\frac{1}{2}$ = 0.5 miles Using Pythagorean theorem- $Diagonal Distance^{2}$ = $Horizontal Distance^{2}$ + $Altitude^{2}$ $Diagonal Distance^{2}$ = $(1.2)^{2}$ + $(0.5)^{2}$ = 1.44 + 0.25 = 1.69 Therefore Diagonal Distance = $\sqrt (1.69)$ = 1.3 miles
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.