Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 1 - Section 1.2 - The Rectangular Coordinate System - 1.2 Problem Set - Page 23: 8

Answer

$(x-h)^2+(y-k)^2=r^2$

Work Step by Step

A circle is defined as the set of all points in the plane that are a fixed distance from a given fixed point. The fixed distance is the radius of the circle, and the fixed point is called the center. If we let $r $ > 0 be the radius, ($h$, $k$) the center, and ($x$, $y$) represent any point on the circle, then ($x$, $y$) is r units from ($h$, $k$). Applying the distance formula: $$\sqrt{(x-h)^2+(y-k)^2} = r$$ Squaring both sides: $$(x-h)^2+(y-k)^2=r^2$$
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