Trigonometry 7th Edition

Published by Cengage Learning

Chapter 1 - Section 1.1 - Angles, Degrees, and Special Triangles - 1.1 Problem Set: 65

Answer

Distance traveled by the bullet in nearest feet = 1414 feet

Work Step by Step

The path of bullet under given conditions will be along hypotenuse of a 45°–45°–90° triangle. Distance traveled by it when it is 1000 feet above ground will be the length of hypotenuse, while length of shorter side is 1000 feet. In a 45°–45°–90° triangle, length of hypotenuse is $\sqrt 2$ times the length of shorter side, Hence- Distance traveled by the bullet = $1000 \times \sqrt 2$ Distance traveled by the bullet = $1000 \times 1.41421$ = 1414.21 feet Distance traveled by the bullet in nearest feet = 1414 feet

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