Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 1 - Section 1.1 - Angles, Degrees, and Special Triangles - 1.1 Problem Set - Page 12: 41

Answer

x = 1

Work Step by Step

We will use given data about triangle ABC and Pythagoras Theorem to solve for 'x'- We know that - $(\sqrt 10)^{2} =(x+2)^{2} + x^{2}$ ( Pythagoras Theorem) Therefore - $10 = (x^{2} + 4 x + 4) + x^{2}$ $10 = 2x^{2} + 4 x + 4 $ $2x^{2} + 4 x - 6 $ = 0 $x^{2} + 2 x - 3 $ = 0 $x^{2} + 3 x -x - 3 $ = 0 $ x (x+3) -1(x+3)$ = 0 $ (x+3) (x-1)$ = 0 Therefore Either x=1 or -3 As x is a length, it can not be negative, Therefore x = 1
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