Answer
$f^{-1}(x) = 4x + 3$
Work Step by Step
$f(x) = \frac{x-3}{4}$
Let $f(x) = y$
$y = \frac{x-3}{4}$
$x = \frac{y-3}{4}$
$4x = y-3$
$4x + 3 = y$
$y = 4x + 3$
$f^{-1}(x) = 4x + 3$
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