## Trigonometry 7th Edition

$f^{-1}(x) = \frac{x+5}{2}$
$f(x) = 2x -5$ Let $y = f(x)$ $y = 2x-5$ $x = 2y-5$ $x + 5 = 2y$ $y = \frac{x+ 5}{2}$ $f^{-1}(x) = \frac{x+5}{2}$