Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 8 - Complex Numbers, Polar Equations, and Parametric Equations - Section 8.5 Polar Equations and Graphs - 8.5 Exercises - Page 391: 81c

Answer

When $\theta$ is close to $0^{\circ}$, we can see that Pluto's distance from the sun is slightly closer than Neptune's distance from the sun. Therefore, Pluto is not always farthest from the sun.

Work Step by Step

$r = \frac{a~(1-e^2)}{1+e~cos~\theta}$ Neptune: $a = 30.10$ $e = 0.009$ $\theta = 0^{\circ}~~~~~~~r = 29.83$ $\theta = 90^{\circ}~~~~~~r = 30.10$ $\theta = 180^{\circ}~~~~~r = 30.37$ $\theta = 270^{\circ}~~~~~r = 30.10$ Pluto: $a = 39.40$ $e = 0.249$ $\theta = 0^{\circ}~~~~~~~r = 29.59$ $\theta = 90^{\circ}~~~~~~r = 36.96$ $\theta = 180^{\circ}~~~~~r = 49.21$ $\theta = 270^{\circ}~~~~~r = 36.96$ We can see the graph of the two orbits below: When $\theta$ is close to $0^{\circ}$, we can see that Pluto's distance from the sun is slightly closer than Neptune's distance from the sun. Therefore, Pluto is not always farthest from the sun.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.